SFN:Math-test
$ \newcommand\cc{\mathcal{C}} \newcommand\set{\mathsf{Set}}
$
Notice that the condition (Sb:b) implies that the functor $U$ preserves image--factorizations:
$ \newcommand\cc{\mathcal{C}} \newcommand\set{\mathsf{Set}}
$
Notice that the condition (Sb:b) implies that the functor $U$ preserves image--factorizations: